The mass defect for the nucleus of helium is $0.0303 \, a.m.u.$ What is the binding energy per nucleon for helium in $MeV$?

If the binding energy of the deuterium is $2.23 \, MeV$, the mass defect in $a.m.u.$ is:

If $M_{O}$ is the mass of an oxygen isotope ${ }_{8}^{17}O$, $M_{p}$ and $M_{n}$ are the masses of a proton and a neutron, respectively, the nuclear binding energy of the isotope is

The correct statement of the following is:

The atomic mass of ${ }_7 N ^{15}$ is $15.000108 \text{ a.m.u.}$ and that of ${ }_8 O ^{16}$ is $15.994915 \text{ a.m.u.}$ If the mass of a proton is $1.007825 \text{ a.m.u.}$,then the minimum energy required to remove the least tightly bound proton is ......... $MeV$.

If the binding energy per nucleon of a nuclide is high,then: