The mass number and the volume of a nucleus a | vedclass

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(C) The radius $R$ of a nucleus is related to its mass number $A$ by the formula $R = R_0 A^{1/3}$, where $R_0$ is a constant.The volume $V$ of a nucl

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$2V$

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(C) The radius $R$ of a nucleus is related to its mass number $A$ by the formula $R = R_0 A^{1/3}$, where $R_0$ is a constant.The volume $V$ of a nucleus is given by $V = \frac{4}{3} \pi R^3$.Substituting the expression for $R$, we get $V = \frac{4}{3} \pi (R_0 A^{1/3})^3 = \frac{4}{3} \pi R_0^3 A$.This shows that the volume $V$ is directly proportional to the mass number $A$ $(V \propto A)$.If the mass number is increased from $A$ to $2A$, the new volume $V'$ will be $V' \propto 2A$.Therefore, $V' = 2V$.

The mass number and the volume of a nucleus are $A$ and $V$ respectively. If the mass number is increased to $2A$, then the volume changes to:

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