The mass of NH_3 produced when 131.8 kg of c | vedclass

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(B) The chemical reaction for the oxidation of cyclohexanecarbaldehyde with Tollen's reagent is:$C_6H_{11}CHO + 2[Ag(NH_3)_2]OH \rightarrow C_6H_{11}C

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$60$

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(B) The chemical reaction for the oxidation of cyclohexanecarbaldehyde with Tollen's reagent is:$C_6H_{11}CHO + 2[Ag(NH_3)_2]OH ightarrow C_6H_{11}COONH_4 + 2Ag + 3NH_3 + H_2O$Molar mass of cyclohexanecarbaldehyde $(C_7H_{12}O)$ = $(7 	imes 12) + (12 	imes 1) + 16 = 84 + 12 + 16 = 112 \ g/mol$.From the stoichiometry,$1 \ mol$ of cyclohexanecarbaldehyde produces $3 \ mol$ of $NH_3$.Moles of cyclohexanecarbaldehyde = $\frac{131.8 	imes 10^3 \ g}{112 \ g/mol} \approx 1176.78 \ mol$.Moles of $NH_3$ produced = $3 	imes 1176.78 = 3530.34 \ mol$.Mass of $NH_3$ = $3530.34 \ mol 	imes 17 \ g/mol = 60015.78 \ g \approx 60 \ kg$.

The mass of $NH_3$ produced when $131.8 \ kg$ of cyclohexanecarbaldehyde undergoes Tollen's test is $..... \ kg$. (Nearest Integer) Molar Mass of $C = 12 \ g/mol$,$N = 14 \ g/mol$,$O = 16 \ g/mol$.

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