The mass of CO_2 that shall be obtained by he | vedclass

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(C) The chemical reaction for the thermal decomposition of limestone is: $CaCO_{3(s)} \xrightarrow{\Delta} CaO_{(s)} + CO_{2(g)}$ From the stoichiomet

Vedclass · Accepted Answer

$3.52$

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(C) The chemical reaction for the thermal decomposition of limestone is: $CaCO_{3(s)} \xrightarrow{\Delta} CaO_{(s)} + CO_{2(g)}$ From the stoichiometry of the reaction,$100 \ g$ of $CaCO_3$ produces $44 \ g$ of $CO_2$. Given that the limestone is $80\%$ pure,the mass of pure $CaCO_3$ in $10 \ kg$ of limestone is: $Mass_{CaCO_3} = 10 \ kg 	imes 0.80 = 8 \ kg$ Using the molar mass ratio: $Mass_{CO_2} = \frac{44 \ kg \ CO_2}{100 \ kg \ CaCO_3} 	imes 8 \ kg \ CaCO_3 = 3.52 \ kg$

The mass of $CO_2$ that shall be obtained by heating $10 \ kg$ of $80\%$ pure limestone $(CaCO_3)$ is $:-$ (in $kg$)

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