The maximum efficiency of a full wave rectifi | vedclass

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(B) The efficiency $(\eta)$ of a rectifier is defined as the ratio of the $DC$ output power to the $AC$ input power.For a full-wave rectifier,the $DC$

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$\frac{8}{\pi^2} 	imes 100 \,\%$

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(B) The efficiency $(\eta)$ of a rectifier is defined as the ratio of the $DC$ output power to the $AC$ input power.For a full-wave rectifier,the $DC$ output power is $P_{dc} = I_{dc}^2 R_L = (\frac{2I_m}{\pi})^2 R_L = \frac{4I_m^2 R_L}{\pi^2}$.The $AC$ input power is $P_{ac} = I_{rms}^2 (R_f + R_L) = (\frac{I_m}{\sqrt{2}})^2 (R_f + R_L) = \frac{I_m^2}{2} (R_f + R_L)$.Assuming the diode resistance $R_f$ is negligible compared to the load resistance $R_L$,the efficiency is $\eta = \frac{P_{dc}}{P_{ac}} = \frac{4I_m^2 R_L / \pi^2}{I_m^2 R_L / 2} = \frac{8}{\pi^2}$.Converting this to a percentage,the maximum efficiency is $\frac{8}{\pi^2} 	imes 100 \% \approx 81.2 \%$.

The maximum efficiency of a full wave rectifier is .........

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