The maximum horizontal range of a projectile | vedclass

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Question

(B) The maximum horizontal range is given by $R_{\max} = \frac{u^2}{g} = 400\, m$ (at $	heta = 45^\circ$).The maximum height attained by a projectile

Vedclass · Accepted Answer

$200$

Vedclass · Answer

(B) The maximum horizontal range is given by $R_{\max} = \frac{u^2}{g} = 400\, m$ (at $	heta = 45^\circ$).The maximum height attained by a projectile is given by $H_{\max} = \frac{u^2 \sin^2 	heta}{2g}$.For the maximum height,the projectile must be projected at $	heta = 90^\circ$,so $H_{\max} = \frac{u^2}{2g}$.Substituting $\frac{u^2}{g} = 400\, m$ into the equation:$H_{\max} = \frac{1}{2} 	imes \left( \frac{u^2}{g} ight) = \frac{1}{2} 	imes 400 = 200\, m$.

The maximum horizontal range of a projectile is $400\, m$. The maximum height attained by it will be ......... $m$.

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