(A) According to Einstein's photoelectric equation,the maximum kinetic energy $K_{max}$ is given by $K_{max} = h\nu - \phi$.Given that for frequency $

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(A) According to Einstein's photoelectric equation,the maximum kinetic energy $K_{max}$ is given by $K_{max} = h\nu - \phi$.Given that for frequency $\nu$,the maximum kinetic energy is $E$,we have:$E = h\nu - \phi$ --- $(1)$When the frequency is increased to $3\nu$,the new maximum kinetic energy $K'_{max}$ is:$K'_{max} = h(3\nu) - \phi = 3h\nu - \phi$ --- $(2)$From equation $(1)$,we can express $h\nu$ as $h\nu = E + \phi$.Substituting this into equation $(2)$:$K'_{max} = 3(E + \phi) - \phi$$K'_{max} = 3E + 3\phi - \phi$$K'_{max} = 3E + 2\phi$.

Class 12 Physics Dual Nature of Radiation and matter Einstein's Photoelectric Equation and Energy Quantum of Radiation

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The maximum kinetic energy of the emitted photoelectrons from a photosensitive material of work function $\phi$,when light of frequency $\nu$ is incident on it,is $E$. If the frequency of the incident light is $3\nu$,the maximum kinetic energy of the emitted photoelectrons is:

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A
$3E + 2\phi$
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$3E - 2\phi$
C
$2E + 3\phi$
D
$2E - 3\phi$

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Dual Nature of Radiation and matter

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Einstein's Photoelectric Equation and Energy Quantum of Radiation

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The maximum kinetic energy of the emitted photoelectrons from a photosensitive material of work function $\phi$,when light of frequency $\nu$ is incident on it,is $E$. If the frequency of the incident light is $3\nu$,the maximum kinetic energy of the emitted photoelectrons is:

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