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(B) The condition for interference maxima in Young's double-slit experiment is given by $\Delta x = d \sin 	heta = n \lambda$,where $n$ is an integer

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$5$

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(B) The condition for interference maxima in Young's double-slit experiment is given by $\Delta x = d \sin 	heta = n \lambda$,where $n$ is an integer.Given that the slit separation $d = 2 \lambda$,we substitute this into the equation:$2 \lambda \sin 	heta = n \lambda$$2 \sin 	heta = n$$\sin 	heta = \frac{n}{2}$Since the maximum value of $\sin 	heta$ is $1$,we have $-1 \le \frac{n}{2} \le 1$,which implies $-2 \le n \le 2$.The possible integer values for $n$ are $-2, -1, 0, 1, 2$.Counting these values,we get a total of $5$ interference maxima.

The maximum number of possible interference maxima for slit-separation equal to twice the wavelength in Young's double-slit experiment is:

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