The maximum value of F which can be applied o | vedclass

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Question

(D) Let both blocks move together with acceleration $a$. For block $M_2$,the only horizontal force providing acceleration is the friction force $f_r$.

Vedclass · Accepted Answer

$F=\mu(M_1+M_2)g$

Vedclass · Answer

(D) Let both blocks move together with acceleration $a$. For block $M_2$,the only horizontal force providing acceleration is the friction force $f_r$. The maximum static friction force is $f_{r,max} = \mu N = \mu M_2 g$. Thus,the maximum acceleration $a_{max}$ of block $M_2$ is $a_{max} = \frac{f_{r,max}}{M_2} = \frac{\mu M_2 g}{M_2} = \mu g$. For the entire system of both blocks $(M_1 + M_2)$ to move together with this maximum acceleration $a_{max}$,the force $F$ applied on $M_1$ must satisfy: $F = (M_1 + M_2) a_{max}$ $F = (M_1 + M_2) \mu g$ $F = \mu(M_1 + M_2) g$ Therefore,the correct option is $(d)$.

The maximum value of $F$ which can be applied on the system shown in the figure so that both blocks move together with the same acceleration is ..........

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