The mean and the median of the following ten | vedclass

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(A) Given the set of $10$ numbers: $10, 22, 26, 29, 34, x, 42, 67, 70, y$ in increasing order.$1$. Mean calculation:$	ext{Mean} = \frac{10 + 22 + 26

Vedclass · Accepted Answer

$\frac{7}{3}$

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(A) Given the set of $10$ numbers: $10, 22, 26, 29, 34, x, 42, 67, 70, y$ in increasing order.$1$. Mean calculation:$	ext{Mean} = \frac{10 + 22 + 26 + 29 + 34 + x + 42 + 67 + 70 + y}{10} = 42$$300 + x + y = 420$$x + y = 120 \quad \dots (i)$$2$. Median calculation:For $10$ observations,the median is the average of the $5^{th}$ and $6^{th}$ terms.$	ext{Median} = \frac{34 + x}{2} = 35$$34 + x = 70$$x = 36$$3$. Finding $y$:Substitute $x = 36$ into equation $(i)$:$36 + y = 120$$y = 84$$4$. Final ratio:$\frac{y}{x} = \frac{84}{36} = \frac{7}{3}$

Class	$0-4$	$4-8$	$8-12$	$12-16$	$16-20$
Frequency	$3$	$9$	$10$	$8$	$6$

The mean and the median of the following ten numbers in increasing order $10, 22, 26, 29, 34, x, 42, 67, 70, y$ are $42$ and $35$ respectively. Then,$\frac{y}{x}$ is equal to:

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