The mean deviation from the mean for the obse | vedclass

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(D) The given observations are $1, 3, 5, 7, 11, 13, 17, 19, 23$.First,we calculate the mean $(\bar{x})$:$\bar{x} = \frac{1+3+5+7+11+13+17+19+23}{9} =

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$6 \frac{2}{9}$

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(D) The given observations are $1, 3, 5, 7, 11, 13, 17, 19, 23$.First,we calculate the mean $(\bar{x})$:$\bar{x} = \frac{1+3+5+7+11+13+17+19+23}{9} = \frac{99}{9} = 11$.The mean deviation about the mean is given by $\frac{1}{n} \sum_{i=1}^{n} |x_i - \bar{x}|$.Mean deviation $= \frac{1}{9} [|1-11| + |3-11| + |5-11| + |7-11| + |11-11| + |13-11| + |17-11| + |19-11| + |23-11|]$.Mean deviation $= \frac{1}{9} [10 + 8 + 6 + 4 + 0 + 2 + 6 + 8 + 12]$.Mean deviation $= \frac{56}{9} = 6 \frac{2}{9}$.

$x_i$	$2$	$4$	$6$	$8$	$10$
$f_i$	$1$	$2$	$3$	$2$	$1$

The mean deviation from the mean for the observations $1, 3, 5, 7, 11, 13, 17, 19, 23$ is

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