The mean free path of a molecule of He gas is | vedclass

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(C) The mean free path $\alpha$ is the resultant of the mean free paths along the three mutually perpendicular coordinate axes $(x, y, z)$.Due to the

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$\frac{\alpha}{\sqrt{3}}$

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(C) The mean free path $\alpha$ is the resultant of the mean free paths along the three mutually perpendicular coordinate axes $(x, y, z)$.Due to the isotropy of the gas,the mean free path along each axis is equal. Let the mean free path along each axis be $a$.Thus,$\alpha = \sqrt{a^2 + a^2 + a^2}$.$\alpha = \sqrt{3a^2} = a\sqrt{3}$.Therefore,the mean free path along any arbitrary coordinate axis is $a = \frac{\alpha}{\sqrt{3}}$.

The mean free path of a molecule of $He$ gas is $\alpha$. Its mean free path along any arbitrary coordinate axis will be ...........

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