The mean of $5$ observations is $16$. If an observation $5$ is replaced by $-5$,the new mean is ...........
- A$14$
- B$15$
- C$17$
- D$18$
Explore More
Similar Questions
In the formula $M = l + \frac{(\frac{n}{2} - cf)}{f} \times c$ for the median,$cf = \ldots \ldots \ldots$
Easy
View SolutionFind the mean,median and mode of the following frequency distribution:
Class $5-10$ $10-15$ $15-20$ $20-25$ $25-30$ $30-35$ Frequency $11$ $20$ $35$ $20$ $8$ $6$
| Class | $5-10$ | $10-15$ | $15-20$ | $20-25$ | $25-30$ | $30-35$ |
| Frequency | $11$ | $20$ | $35$ | $20$ | $8$ | $6$ |
Difficult
View SolutionFind the median of the following frequency distribution:
Class $65-85$ $85-105$ $105-125$ $125-145$ $145-165$ $165-185$ $185-205$ Frequency $4$ $5$ $13$ $20$ $14$ $8$ $4$
| Class | $65-85$ | $85-105$ | $105-125$ | $125-145$ | $145-165$ | $165-185$ | $185-205$ |
| Frequency | $4$ | $5$ | $13$ | $20$ | $14$ | $8$ | $4$ |
Medium
View SolutionFor a given frequency distribution,$A=49.5, \Sigma f_{i}=40, \Sigma f_{i} u_{i}=-5$ and $c=20$. Then,mean $\bar{x}=$ ............
Easy
View SolutionThe median class of the following frequency distribution is ...........
Class $10-20$ $20-30$ $30-40$ $40-50$ $50-60$ $60-70$ $70-80$ Frequency $6$ $10$ $5$ $6$ $4$ $2$ $2$
| Class | $10-20$ | $20-30$ | $30-40$ | $40-50$ | $50-60$ | $60-70$ | $70-80$ |
| Frequency | $6$ | $10$ | $5$ | $6$ | $4$ | $2$ | $2$ |
Easy
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo