(C) Let the four observations be $x_1, x_2, x_3,$ and $x_4$. Given,the mean $(\bar{x}) = 3$ and the number of observations $n = 4$. The sum of the squ

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(C) Let the four observations be $x_1, x_2, x_3,$ and $x_4$. Given,the mean $(\bar{x}) = 3$ and the number of observations $n = 4$. The sum of the squares of the observations is $\sum x_i^2 = 48$. The formula for standard deviation $(SD)$ is: $SD = \sqrt{\frac{\sum x_i^2}{n} - (\bar{x})^2}$ Substituting the given values: $SD = \sqrt{\frac{48}{4} - (3)^2}$ $SD = \sqrt{12 - 9}$ $SD = \sqrt{3}$

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The mean of four observations is $3$. If the sum of the squares of these observations is $48$,then their standard deviation is

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The mean of four observations is $3$. If the sum of the squares of these observations is $48$,then their standard deviation is

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