The melting point of Zn is lower as compared | vedclass

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(D) The electronic configuration of $Zn$ is $[Ar] 3d^{10} 4s^2$. Due to the completely filled $d$-orbitals,the $d$-electrons in $Zn$ do not participat

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Both $A$ and $C$

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(D) The electronic configuration of $Zn$ is $[Ar] 3d^{10} 4s^2$. Due to the completely filled $d$-orbitals,the $d$-electrons in $Zn$ do not participate in metallic bonding. Metallic bonding is primarily responsible for the high melting points of transition metals,which involves the participation of $(n-1)d$ electrons. Since $Zn$ lacks unpaired $d$-electrons,the strength of its metallic bonds is significantly lower than that of other $3d$ transition elements,resulting in a lower melting point.

List-$I$ (Substances)	List-$II$ (Composition)
$A$. Plaster of Paris	$i$. $CaSO_4 \cdot 1/2H_2O$
$B$. Epsomite	$ii$. $MgSO_4 \cdot 7H_2O$
$C$. Kieserite	$iii$. $MgSO_4 \cdot H_2O$
$D$. Gypsum	$iv$. $CaSO_4 \cdot 2H_2O$
	$v$. $CaSO_4$

The melting point of $Zn$ is lower as compared to those of the other elements of the $3d$ series because:

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