The metal salts formed during the softening o | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) $Clark's$ method is used to remove temporary hardness of water by adding calculated amounts of lime,$Ca(OH)_2$.The chemical reactions involved are

Vedclass · Accepted Answer

$CaCO_3$ and $Mg(OH)_2$

Vedclass · Answer

(B) $Clark's$ method is used to remove temporary hardness of water by adding calculated amounts of lime,$Ca(OH)_2$.The chemical reactions involved are:$Ca(HCO_3)_2 + Ca(OH)_2 \rightarrow 2CaCO_3(s) + 2H_2O(l)$$Mg(HCO_3)_2 + 2Ca(OH)_2 \rightarrow 2CaCO_3(s) + Mg(OH)_2(s) + 2H_2O(l)$As seen from the reactions,the insoluble metal salts formed are $CaCO_3$ and $Mg(OH)_2$.

The metal salts formed during the softening of hard water using $Clark's$ method are:

Similar Questions

Explain: Proton $(H^{+})$ does not exist in aqueous solution.

Water obtained by purification with organic ion exchange resins is:

Explain the difference between hard water and soft water.

Which of the following is not correct for $D_2O$?

Assertion $(A)$ : $NaCl$ is less soluble in heavy water than in ordinary water.
Reason $(R)$ : Dielectric constant of ordinary water is more than that of heavy water.
The correct answer is

Vedclass Test Series

Exam Paper Generator

Online Exam Module