The minimum energy required to launch a satellite of mass $m$ from the surface of a planet of mass $M$ and radius $R$ into a circular orbit at an altitude of $2R$ is

  • A
    $\frac{5 GMm}{6 R}$
  • B
    $\frac{2 GMm}{3 R}$
  • C
    $\frac{GMm}{2 R}$
  • D
    $\frac{GMm}{3 R}$

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Similar Questions

$A$ satellite of mass $m$,initially at rest on the Earth,is launched into a circular orbit at a height equal to the radius of the Earth. The minimum energy required is

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Match the following columns.
$A$. Potential energy of satellite$I$. Positive
$B$. Total energy of satellite$II$. Negative
$C$. Kinetic energy of satellite$III$. Zero
$D$. Gravitational potential energy of satellite at infinity$IV$. Infinity

Obtain an expression for the total energy of a satellite revolving around the Earth.

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The additional kinetic energy to be provided to a satellite of mass $m$ revolving around a planet of mass $M$ to transfer it from a circular orbit of radius $R_1$ to another of radius $R_2$ $(R_2 > R_1)$ is:

Choose the correct alternative:
$(a)$ If the zero of potential energy is at infinity,the total energy of an orbiting satellite is negative of its kinetic/potential energy.
$(b)$ The energy required to launch an orbiting satellite out of Earth's gravitational influence is more/less than the energy required to project a stationary object at the same height (as the satellite) out of Earth's influence.

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