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(D) The force $F_{1}$ required to push the body up the incline is given by $F_{1} = mg(\sin 	heta + \mu \cos 	heta)$.The force $F_{2}$ required to p

Vedclass · Accepted Answer

$3$

Vedclass · Answer

(D) The force $F_{1}$ required to push the body up the incline is given by $F_{1} = mg(\sin 	heta + \mu \cos 	heta)$.The force $F_{2}$ required to prevent the body from sliding down the incline is given by $F_{2} = mg(\sin 	heta - \mu \cos 	heta)$.Taking the ratio of the two forces:$\frac{F_{1}}{F_{2}} = \frac{mg(\sin 	heta + \mu \cos 	heta)}{mg(\sin 	heta - \mu \cos 	heta)} = \frac{\sin 	heta + \mu \cos 	heta}{\sin 	heta - \mu \cos 	heta}$.Dividing the numerator and denominator by $\cos 	heta$:$\frac{F_{1}}{F_{2}} = \frac{	an 	heta + \mu}{	an 	heta - \mu}$.Given that $	an 	heta = 2\mu$,substitute this value into the equation:$\frac{F_{1}}{F_{2}} = \frac{2\mu + \mu}{2\mu - \mu} = \frac{3\mu}{\mu} = 3$.

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