The minimum intensity of sound is zero at a p | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) When two sound waves of nearly equal frequencies superpose at a point, they produce the phenomenon of beats.The resultant intensity $I$ at any poi

Vedclass · Accepted Answer

At the point of observation, the amplitudes of two $S.H.M.$ produced by two sources are equal and both the $S.H.M.$ are along the same straight line

Vedclass · Answer

(C) When two sound waves of nearly equal frequencies superpose at a point, they produce the phenomenon of beats.The resultant intensity $I$ at any point is given by $I = I_1 + I_2 + 2\sqrt{I_1 I_2} \cos(\phi)$, where $\phi$ is the phase difference.For the intensity to be minimum $(I_{\min} = 0)$, the condition is $I_1 = I_2$ and $\cos(\phi) = -1$.This implies that the amplitudes of the two $S.H.M.$ produced by the sources must be equal, and they must be traveling along the same straight line to interfere destructively at the point of observation.

The minimum intensity of sound is zero at a point due to two sources of nearly equal frequencies, when

Similar Questions

$A$ pair of tuning forks produces $2$ beats in a time interval of $0.4 \ s$. The beat frequency is .... $Hz$.

The sound waves of wavelengths $5 \,m$ and $6 \,m$ produce $30$ beats in $3 \,s$. The velocity of sound is (in $\,m/s$)

The wavelengths of two sound notes in air are $\frac{40}{195} \,m$ and $\frac{40}{193} \,m$. Each note produces $9$ beats per second separately with a third note of fixed frequency. The velocity of sound in air in $m/s$ is

When two sound waves are superimposed,beats are produced when they have

$A$ tuning fork $A$ of frequency $200 \ Hz$ is sounded with fork $B,$ the number of beats per second is $5.$ By putting some wax on $A,$ the number of beats increases to $8.$ The frequency of fork $B$ is .... $Hz$

Vedclass Test Series

Exam Paper Generator

Online Exam Module