The minimum value of effective capacitance that can be obtained by combining $3$ capacitors of capacitances $1 \ pF, 2 \ pF$ and $4 \ pF$ is

For the arrangement of capacitors as shown in the circuit,the effective capacitance between the points $A$ and $B$ is (capacitance of each capacitor is $4 \mu F$): (in $\mu F$)

Four identical capacitors are connected in series with a battery of $emf$ $10 \ V$. Point $X$ is grounded. Find the potential at point $A$ in $V$.

The total capacity of the system of capacitors shown in the adjoining figure between the points $A$ and $B$ is $..... \ \mu F$.

Three capacitors of capacitance $C$ ($\mu F$) are connected in parallel, and this combination is connected in series with another capacitor of capacitance $C$. If the effective capacitance is $3.75 \mu F$, then the capacity of each capacitor is: (in $\mu F$)

Three capacitors $1\,\mu F$,$2\,\mu F$,and $4\,\mu F$ are connected in series to a $10\,V$ source. The charge on the plates of the middle capacitor is: