The minimum wavelength of X-rays produced by | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The kinetic energy gained by an electron accelerated through a potential difference $V$ is given by $K = eV$,where $e$ is the charge of the electr

Vedclass · Accepted Answer

$\frac{1}{V}$

Vedclass · Answer

(C) The kinetic energy gained by an electron accelerated through a potential difference $V$ is given by $K = eV$,where $e$ is the charge of the electron.When this electron strikes the target,the maximum energy of the emitted $X$-ray photon is equal to the kinetic energy of the electron,i.e.,$E_{\max} = h
u_{\max} = eV$.Since the frequency $
u = \frac{c}{\lambda}$,the minimum wavelength $\lambda_{\min}$ corresponds to the maximum energy:$\lambda_{\min} = \frac{hc}{E_{\max}} = \frac{hc}{eV}$.Since $h$,$c$,and $e$ are constants,we have $\lambda_{\min} \propto \frac{1}{V}$.Therefore,the correct option is $C$.

The minimum wavelength of $X$-rays produced by an electron accelerated through a potential difference of $V$ volts is proportional to:

Similar Questions

When $X$-rays pass through a high-intensity uniform magnetic field,they:

Which of the following is accompanied by the characteristic $X-$ray emission?

When cathode rays (tube voltage $\sim 10 \ kV$) collide with the anode of high atomic weight,then we get:

For the production of characteristic $K_{\gamma}$ $X$-ray,the electron transition is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module