The minute-hand of a clock is 14 , cm long. T | vedclass

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Question

(A) The minute hand of a clock completes a full circle $(360^{\circ})$ in $60 \, min$.Therefore,the angle covered by the minute hand in $30 \, min$ is

Vedclass · Accepted Answer

$308$

Vedclass · Answer

(A) The minute hand of a clock completes a full circle $(360^{\circ})$ in $60 \, min$.Therefore,the angle covered by the minute hand in $30 \, min$ is $	heta = \frac{360^{\circ}}{60} 	imes 30 = 180^{\circ}$.The length of the minute hand is the radius of the circle,so $r = 14 \, cm$.The area covered by the minute hand is the area of the sector formed by the angle $	heta$:$	ext{Area} = \frac{	heta}{360^{\circ}} 	imes \pi r^2$$	ext{Area} = \frac{180^{\circ}}{360^{\circ}} 	imes \frac{22}{7} 	imes 14 	imes 14$$	ext{Area} = \frac{1}{2} 	imes 22 	imes 2 	imes 14$$	ext{Area} = 11 	imes 28 = 308 \, cm^2$.

The minute-hand of a clock is $14 \, cm$ long. The area covered by the minute hand in $30 \, min$ is.............$cm^2$

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