The molar conductivities $\Lambda_{NaOH}^o$ and $\Lambda_{HCl}^o$ at infinite dilution in water at $25 ^\circ C$ are $91.0$ and $426.2 \ S \ cm^2/mol$ respectively. To calculate $\Lambda_{CH_3COOH}^o$,the additional value required is:

The values of $\lambda^{\infty}_m$ for $NH_4Cl$,$NaOH$,and $NaCl$ are $129.8$,$248.1$,and $126.4 \ \Omega^{-1} \ cm^2 \ mol^{-1}$ respectively. Calculate $\lambda^{\infty}_m$ for $NH_4OH$ solution (in $\Omega^{-1} \ cm^2 \ mol^{-1}$).

Calculate the molar conductivity of $CH_2ClCOOH$ at zero concentration if molar conductivities of $HCl$,$KCl$,and $CH_2ClCOOK$ at zero concentration are $4.2$,$1.4$,and $1.1 \ \Omega^{-1} \ cm^2 \ mol^{-1}$ respectively.

What is conductivity? On what factors does conductivity depend?

Electrical conductance through metals is called metallic or electronic conductance and is due to the movement of electrons. The electronic conductance depends on

Resistance of a conductivity cell filled with $0.1 \ mol \ L^{-1}$ $NaCl$ is $100 \ \Omega$. If the resistance of the same cell when filled with $0.02 \ mol \ L^{-1}$ $NaCl$ solution is $258 \ \Omega$,the conductivity of $0.02 \ mol \ L^{-1}$ $NaCl$ solution is (Conductivity of $0.1 \ mol \ L^{-1}$ $NaCl$ is $1.29 \ S \ m^{-1}$) (in $S \ m^{-1}$)