The molar conductivity of $0.02 \ M$ $KCl$ solution is $410 \ \Omega^{-1} \ cm^2 \ mol^{-1}$ at $25^{\circ} C$. Calculate its conductivity?
- A$8.2 \times 10^{-3} \ \Omega^{-1} \ cm^{-1}$
- B$2.8 \times 10^{-3} \ \Omega^{-1} \ cm^{-1}$
- C$4.1 \times 10^{-3} \ \Omega^{-1} \ cm^{-1}$
- D$5.4 \times 10^{-3} \ \Omega^{-1} \ cm^{-1}$
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