The molar heat capacity in a process of a dia | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) For a diatomic gas,the internal energy change is given by $dU = C_V dT = \frac{5}{2} R dT$. From the first law of thermodynamics,$dU = dQ - dW$. G

Vedclass · Accepted Answer

$\frac{10}{3}R$

Vedclass · Answer

(C) For a diatomic gas,the internal energy change is given by $dU = C_V dT = \frac{5}{2} R dT$. From the first law of thermodynamics,$dU = dQ - dW$. Given $dQ = Q$ and $dW = \frac{Q}{4}$,we have $dU = Q - \frac{Q}{4} = \frac{3Q}{4}$. Substituting $dU$ into the internal energy equation: $\frac{3Q}{4} = \frac{5}{2} R dT$,which gives $dT = \frac{3Q}{4} 	imes \frac{2}{5R} = \frac{3Q}{10R}$. The molar heat capacity $C$ is defined as $C = \frac{dQ}{dT}$. Substituting the values: $C = \frac{Q}{\frac{3Q}{10R}} = \frac{10}{3}R$.

Column-$I$	Column-$II$
$(A)$ Linnaeus	$(i)$ First to discover viruses
$(B)$ Ivanowsky	$(ii)$ First to discover lichens
$(C)$ Iyengar	$(iii)$ Father of Indian Bryology
$(D)$ Tulasne	$(iv)$ Father of Taxonomy
$(E)$ Shiv Ram Kashyap	$(v)$ Father of modern Phycology in India

The molar heat capacity in a process of a diatomic gas,if it does a work of $\frac{Q}{4}$ when a heat of $Q$ is supplied to it,is:

Similar Questions

The cold junction of a thermocouple is maintained at $10\,^{\circ}C$. No thermo $e.m.f.$ is developed when the hot junction is maintained at $530\,^{\circ}C$. The neutral temperature is ................ $^{\circ}C$.

The imperfect fungi which are decomposers of litter and help in mineral cycling belong to

Three point charges are placed at the corners of an equilateral triangle. Assuming only electrostatic forces are acting,which of the following statements is true?

In a triangle,if $b=20, c=21$ and $\sin A=\frac{3}{5}$,then $a$ is equal to :

Vedclass Test Series

Exam Paper Generator

Online Exam Module