The molar solution of sulphuric acid is equal | vedclass

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(B) The molarity $(M)$ of a solution is defined as the number of moles of solute per liter of solution.For sulphuric acid $(H_2SO_4)$,the n-factor (ba

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$2\,N$ solution

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(B) The molarity $(M)$ of a solution is defined as the number of moles of solute per liter of solution.For sulphuric acid $(H_2SO_4)$,the n-factor (basicity) is $2$ because it releases $2$ $H^+$ ions per molecule.The relationship between normality $(N)$ and molarity $(M)$ is given by: $N = M 	imes 	ext{n-factor}$.For a $1\,M$ solution of $H_2SO_4$,$N = 1 	imes 2 = 2\,N$.Therefore,the molar solution of sulphuric acid is equal to $2\,N$ solution.

The molar solution of sulphuric acid is equal to:

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