The molar specific heat of an ideal gas at constant pressure and constant volume is $C_p$ and $C_v$ respectively. If $R$ is the universal gas constant and the ratio of $C_p$ to $C_v$ is $\gamma$,then $C_v$ is equal to:

  • A
    $\frac{\gamma-1}{R}$
  • B
    $\frac{1-\gamma}{1+\gamma}$
  • C
    $\frac{1+\gamma}{1-\gamma}$
  • D
    $\frac{R}{\gamma-1}$

Explore More

Similar Questions

According to the law of equipartition of energy, the molar specific heat of a diatomic gas at constant volume, where the molecule has one additional vibrational mode, is:

For a gas,$\frac{R}{C_{v}} = 0.67$. This gas is made up of molecules which are

The correct relation between the degree of freedom $f$ and the ratio of specific heat $\gamma$ is

$A$ mixture of one mole of monoatomic gas and one mole of a diatomic gas (rigid) is kept at room temperature $\left(27^{\circ} C\right)$. The ratio of the specific heat of these gases at constant volume is:

Find the ratio of specific heat at constant pressure $(C_p)$ to the specific heat at constant volume $(C_v)$ for $NH_3$.

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo