The molarity of a $1 \ molal$ glucose solution having a density of $1.2 \ g/mL$ is: (in $M$)

If the concentration of glucose $(C_{6}H_{12}O_{6})$ in blood is $0.72 \ g \ L^{-1}$,the molarity of glucose in blood is $..... \times 10^{-3} \ M$. (Nearest integer)
(Given: Atomic mass of $C=12, H=1, O=16 \ u$)

The number of moles of solute per $kg$ of a solvent is called its

$60 \ g$ of $CH_3COOH$ is dissolved in $1 \ dm^3$ of solvent. What is the molality of the solution (in $m$)? (Density $= 1.25 \ g / cm^3$)

The volume of water added to $500 \ mL$ of $0.5 \ M \ NaOH$ solution so that its strength becomes $10 \ mg \ mL^{-1}$ will be .......... $mL$.

Assertion: One molal aqueous solution of glucose contains $180 \, g$ of glucose in $1 \, kg$ water.
Reason: Solution containing one mole of solute in $1000 \, g$ of solvent is called one molal solution.