The molarity of a solution containing $15 \text{ g}$ of $\text{NaOH}$ in $900 \text{ ml}$ of solution will be . . . . . . . (in $\text{ M}$)

  • A
    $0.42$
  • B
    $0.042$
  • C
    $4.2$
  • D
    $42.0$

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