The molarity of the solution prepared by diss | vedclass

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(D) $1$. Calculate the molar mass of oxalic acid dihydrate $(H_{2}C_{2}O_{4} \cdot 2H_{2}O)$:$M_w = (2 	imes 1.0) + (2 	imes 12.0) + (4 	imes 16.0)

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$20$

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(D) $1$. Calculate the molar mass of oxalic acid dihydrate $(H_{2}C_{2}O_{4} \cdot 2H_{2}O)$:$M_w = (2 	imes 1.0) + (2 	imes 12.0) + (4 	imes 16.0) + 2 	imes (2 	imes 1.0 + 16.0) = 2 + 24 + 64 + 36 = 126 \ g \ mol^{-1}$.$2$. Calculate the number of moles of oxalic acid:$n = \frac{	ext{mass}}{M_w} = \frac{6.3 \ g}{126 \ g \ mol^{-1}} = 0.05 \ mol$.$3$. Calculate the molarity $(M)$ of the solution:$M = \frac{n}{V(L)} = \frac{0.05 \ mol}{0.250 \ L} = 0.2 \ mol \ L^{-1}$.$4$. Express the molarity in the form $x 	imes 10^{-2}$:$0.2 = 20 	imes 10^{-2}$.Therefore,the value of $x$ is $20$.

The molarity of the solution prepared by dissolving $6.3 \ g$ of oxalic acid $(H_{2}C_{2}O_{4} \cdot 2H_{2}O)$ in $250 \ mL$ of water in $mol \ L^{-1}$ is $x \times 10^{-2}$. The value of $x$ is ..... . (Nearest integer)
[Atomic mass : $H: 1.0, C: 12.0, O: 16.0]$

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The molarity of the solution prepared by dissolving $6.3 \ g$ of oxalic acid $(H_{2}C_{2}O_{4} \cdot 2H_{2}O)$ in $250 \ mL$ of water in $mol \ L^{-1}$ is $x \times 10^{-2}$. The value of $x$ is ..... . (Nearest integer)[Atomic mass : $H: 1.0, C: 12.0, O: 16.0]$