The moment of inertia of a body about a given | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Given: Moment of inertia $I = 1.2 ~kg \cdot m^2$,Rotational Kinetic Energy $K.E. = 1500 ~J$,Angular acceleration $\alpha = 25 ~rad/s^2$,Initial an

Vedclass · Accepted Answer

$2$

Vedclass · Answer

(B) Given: Moment of inertia $I = 1.2 ~kg \cdot m^2$,Rotational Kinetic Energy $K.E. = 1500 ~J$,Angular acceleration $\alpha = 25 ~rad/s^2$,Initial angular velocity $\omega_0 = 0$. Step $1$: Calculate the final angular velocity $\omega$ using the rotational kinetic energy formula: $K.E. = \frac{1}{2} I \omega^2$ $1500 = \frac{1}{2} 	imes 1.2 	imes \omega^2$ $1500 = 0.6 	imes \omega^2$ $\omega^2 = \frac{1500}{0.6} = 2500$ $\omega = 50 ~rad/s$. Step $2$: Calculate the time $t$ using the kinematic equation for rotation: $\omega = \omega_0 + \alpha t$ $50 = 0 + 25 	imes t$ $t = \frac{50}{25} = 2 ~s$.

The moment of inertia of a body about a given axis is $1.2 ~kg \cdot m^2$. Initially,the body is at rest. In order to produce a rotational kinetic energy of $1500 ~J$,an angular acceleration of $25 ~rad/s^2$ must be applied about the axis for a time duration of: (in $~s$)

Similar Questions

Velocity and acceleration vectors of a charged particle moving perpendicular to the direction of a magnetic field at a given instant of time are $\overrightarrow{v}=2 \hat{i}+c \hat{j}$ and $\overrightarrow{a}=3 \hat{i}+4 \hat{j}$ respectively. Then the value of $c$ is

The catalyst and promoter respectively used in the Haber's process of industrial synthesis of ammonia are

If the lines $x^2+2xy-35y^2-4x+44y-12=0$ and $5x+\lambda y-8=0$ are concurrent,then the value of $\lambda$ is

Starting from rest, the time taken by a body sliding down on a rough inclined plane at $45^{\circ}$ with the horizontal is twice the time taken to travel on a smooth plane of the same inclination and same distance. Then the coefficient of kinetic friction is:

In the circuit shown in the following figure,the value of $Y$ is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module