The moment of inertia of a disc of mass $M$ and radius $R$ about a tangent to its rim in its plane is

  • A
    $ \frac{5}{4}MR^2 $
  • B
    $ \frac{2}{3}MR^2 $
  • C
    $ \frac{3}{2}MR^2 $
  • D
    $ \frac{4}{5}MR^2 $

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Similar Questions

Seven identical coins are rigidly arranged on a flat table in the pattern shown below,so that each coin touches its neighbours. Each coin is a thin disc of mass $m$ and radius $r$. Note that the moment of inertia of an individual coin about an axis passing through its centre and perpendicular to the plane of the coin is $\frac{m r^2}{2}$. The moment of inertia of the system of seven coins about an axis that passes through the point $P$ (the centre of the coin positioned directly to the right of the central coin) and perpendicular to the plane of the coins is ..........$m r^2$.

Two thin discs each of mass $M$ and radius $r$ are attached as shown in the figure to form a rigid body. The rotational inertia of this body about an axis perpendicular to the plane of disc $B$ and passing through its centre is (in $,Mr^2$)

Four thin metal rods,each of mass $M$ and length $L$,are welded end to end to form a square. The moment of inertia of the system about an axis passing through the centre of the square and perpendicular to its plane is

Match Column-$I$ with Column-$II$:
Column-$I$Column-$II$
$(1)$ Perpendicular Axis Theorem$(a)$ $I = I_C + Md^2$
$(2)$ Parallel Axis Theorem$(b)$ $I_z = I_x + I_y$

Where, $d =$ distance between two parallel axes.

The moment of inertia of a rod of mass $M$ and length $L$ about an axis passing through a point midway between the center and the end is:

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