The momentum of a photon is 3.3 times 10^{-29 | vedclass

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Question

(D) The momentum $p$ of a photon is related to its frequency $
u$ by the formula: $p = \frac{h
u}{c}$.Rearranging for frequency $
u$,we get: $
u =

Vedclass · Accepted Answer

$1.5 	imes 10^{13} \ Hz$

Vedclass · Answer

(D) The momentum $p$ of a photon is related to its frequency $
u$ by the formula: $p = \frac{h
u}{c}$.Rearranging for frequency $
u$,we get: $
u = \frac{pc}{h}$.Given: $p = 3.3 	imes 10^{-29} \ kg \ m/s$,$c = 3 	imes 10^8 \ m/s$,and Planck's constant $h = 6.6 	imes 10^{-34} \ J \ s$.Substituting the values: $
u = \frac{3.3 	imes 10^{-29} 	imes 3 	imes 10^8}{6.6 	imes 10^{-34}}$.$
u = \frac{9.9 	imes 10^{-21}}{6.6 	imes 10^{-34}} = 1.5 	imes 10^{13} \ Hz$.

The momentum of a photon is $3.3 \times 10^{-29} \ kg \ m/s$. Its frequency will be

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