The momentum of a photon of energy 1 , MeV in | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The energy of the photon is given as $E = 1 \, MeV = 1 	imes 10^6 \, eV$.Converting energy into Joules: $E = 10^6 	imes 1.6 	imes 10^{-19} \, J

Vedclass · Accepted Answer

$5 	imes 10^{-22}$

Vedclass · Answer

(A) The energy of the photon is given as $E = 1 \, MeV = 1 	imes 10^6 \, eV$.Converting energy into Joules: $E = 10^6 	imes 1.6 	imes 10^{-19} \, J = 1.6 	imes 10^{-13} \, J$.The momentum $p$ of a photon is related to its energy $E$ by the formula $p = E/c$,where $c$ is the speed of light $(c \approx 3 	imes 10^8 \, m/s)$.Substituting the values: $p = \frac{1.6 	imes 10^{-13} \, J}{3 	imes 10^8 \, m/s}$.$p \approx 0.533 	imes 10^{-21} \, kg \, m/s$.$p \approx 5.33 	imes 10^{-22} \, kg \, m/s$.Rounding to the nearest given option,the correct value is $5 	imes 10^{-22} \, kg \, m/s$.

The momentum of a photon of energy $1 \, MeV$ in $kg \, m/s$ will be:

Similar Questions

The energy of a photon with a wavelength of $\lambda = 4000 \ \mathring{A}$ is equal to ... $eV$.

What should be the velocity of an electron so that its momentum becomes equal to that of a photon of wavelength $5200 \, \mathring{A}$? (Given: $h = 6.63 \times 10^{-34} \, J \cdot s$, $m_e = 9.1 \times 10^{-31} \, kg$)

What is the momentum of a photon with a frequency of $10^9 \ Hz$?

If the energy of a photon is expressed in units of $KeV$ and the wavelength in units of $\mathring{A}$,then the energy of the photon can be calculated by:

If the wavelength of a photon is $4000 \text{ Å}$,then its energy will be

Vedclass Test Series

Exam Paper Generator

Online Exam Module