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(C) The acidity of non-metal oxides increases with an increase in the oxidation state of the central atom. Calculating the oxidation states of nitroge

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$N_2O_5$

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(C) The acidity of non-metal oxides increases with an increase in the oxidation state of the central atom. Calculating the oxidation states of nitrogen in the given oxides: $NO_2$: $x + 2(-2) = 0 \implies x = +4$ $N_2O_4$: $2x + 4(-2) = 0 \implies x = +4$ $N_2O_5$: $2x + 5(-2) = 0 \implies x = +5$ $N_2O_3$: $2x + 3(-2) = 0 \implies x = +3$ Since $N_2O_5$ has the highest oxidation state of $+5$, it is the most acidic oxide among the given compounds.

The most acidic among the following compounds is

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