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Question

(A) In the contact process,$SO_3$ gas is absorbed in concentrated $H_2SO_4$ $(98\%)$ to form oleum $(H_2S_2O_7)$.This is because $SO_3$ reacts directl

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$98\% \ H_2SO_4$

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(A) In the contact process,$SO_3$ gas is absorbed in concentrated $H_2SO_4$ $(98\%)$ to form oleum $(H_2S_2O_7)$.This is because $SO_3$ reacts directly with water to form a dense fog of $H_2SO_4$ droplets,which is difficult to condense.Therefore,$98\% \ H_2SO_4$ is used as the absorbing agent to produce oleum,which is then diluted with water to get $H_2SO_4$ of the desired concentration.The reaction is: $H_2SO_4 + SO_3 	o H_2S_2O_7$.

The most efficient agent for the absorption of $SO_3$ is

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