The most stable carbanion among the following | vedclass

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(D) The stability of a carbanion is increased by electron-withdrawing groups $(EWG)$ and decreased by electron-donating groups $(EDG)$ attached to the

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$p-NO_2-C_6H_4-CH_2^-$

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(D) The stability of a carbanion is increased by electron-withdrawing groups $(EWG)$ and decreased by electron-donating groups $(EDG)$ attached to the carbon bearing the negative charge.$1.$ Option $A$ is an alkyl carbanion with a phenyl group further away,providing minimal stabilization.$2.$ Option $B$ is a benzyl carbanion,stabilized by resonance with the phenyl ring.$3.$ Option $C$ has a $-OCH_3$ group,which is an electron-donating group (via $+M$ effect),thus destabilizing the carbanion.$4.$ Option $D$ has a $-NO_2$ group,which is a strong electron-withdrawing group (via $-M$ and $-I$ effects). It effectively disperses the negative charge through resonance,making it the most stable carbanion among the given options.

The most stable carbanion among the following is

Similar Questions

Arrange the following carbocations in increasing order of stability:
$1. \, (CH_3)_2 - \overset{+}{C} - CH_2 - CH_3$
$2. \, (CH_3)_3 - \overset{+}{C}$
$3. \, (CH_3)_2 - \overset{+}{C} H$
$4. \, CH_3 - \overset{+}{C} H_2$
$5. \, \overset{+}{C} H_3$

What is the order of stability of carbon free radicals among ${3^\circ}$,${2^\circ}$,${1^\circ}$,and $\mathop C\limits^\bullet {H_3}$?

The orbital picture of a singlet carbene $(:CH_2)$ can be drawn as:

The stability of the following carbocations decreases in the order:

The orbital picture of a triplet carbene can be drawn as

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