The most stable carbocation from the followin | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The stability of carbocations is determined by the electronic effects of the substituents attached to the benzene ring.$1$. In $p$-methoxybenzyl c

Vedclass · Accepted Answer

Vedclass · Answer

(A) The stability of carbocations is determined by the electronic effects of the substituents attached to the benzene ring.$1$. In $p$-methoxybenzyl carbocation,the $-OCH_3$ group at the para position exerts a strong $+M$ (mesomeric) effect,which significantly stabilizes the positive charge through resonance.$2$. In $p$-methylbenzyl carbocation,the $-CH_3$ group provides stability through the $+H$ (hyperconjugation) effect.$3$. In $m$-methoxybenzyl carbocation,the $-OCH_3$ group exerts a $-I$ (inductive) effect because it is at the meta position,which destabilizes the carbocation.$4$. The benzyl carbocation has no additional substituents for stabilization.Therefore,the order of stability is: $p$-methoxybenzyl carbocation > $p$-methylbenzyl carbocation > benzyl carbocation > $m$-methoxybenzyl carbocation.The most stable carbocation is the $p$-methoxybenzyl carbocation.

The most stable carbocation from the following is:

Similar Questions

What is the correct order of stability for the given carbocations?
$(i) \ CH_3^+ \quad (ii) \ CH_3CH_2^+ \quad (iii) \ CH_3OCH_2^+$

Which of the following cannot exist at room temperature?

Arrange the following carbanions in the decreasing order of stability:
$I. \ p-Br-C_6H_4-CH_2^-$
$II. \ C_6H_5-CH_2^-$
$III. \ p-CH_3O-C_6H_4-CH_2^-$
$IV. \ p-CHO-C_6H_4-CH_2^-$
$V. \ p-CH_3-C_6H_4-CH_2^-$
Choose the correct answer from the options given below:

The product of the rearrangement of the given oxyallyl cation is:

The incorrect statement about carbene $(CH_2)$ is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module