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Question

(B) The correct option is $B$. The conversion of $2-$phenylpropanamide into $1-$phenylethylamine involves the loss of a carbonyl carbon atom,which is

Vedclass · Accepted Answer

$Br_{2}, NaOH$

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(B) The correct option is $B$. The conversion of $2-$phenylpropanamide into $1-$phenylethylamine involves the loss of a carbonyl carbon atom,which is characteristic of the Hofmann bromamide degradation reaction.The reaction is as follows:$CH_{3}CH(Ph)CONH_{2} + Br_{2} + 4NaOH \rightarrow CH_{3}CH(Ph)NH_{2} + Na_{2}CO_{3} + 2NaBr + 2H_{2}O$In this reaction,the amide is treated with bromine in an aqueous or ethanolic solution of sodium hydroxide. The alkyl or aryl group migrates from the carbonyl carbon to the nitrogen atom,resulting in the formation of a primary amine with one carbon atom less than the starting amide.

The most suitable reagent for the conversion of $2-$phenylpropanamide into $1-$phenylethylamine is $....$

Similar Questions

Which of the following amines cannot be prepared by Gabriel phthalimide synthesis?

Indicate which nitrogen compound amongst the following would undergo Hofmann's reaction (i.e.,reaction with $Br_2$ and strong $KOH$) to furnish the primary amine $(R-NH_2)$.

In which case is an alkylamine not formed?

Which of the following reactions occurs by the removal of a $-CO-$ group from an amide?

Which of the following reactions does not give an aldehyde as a product?

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