The negation of (p wedge (sim q)) vee (sim p) | vedclass

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(A) Let the given expression be $S = (p \wedge (\sim q)) \vee (\sim p)$.Using the distributive law,we have:$S = (p \vee (\sim p)) \wedge ((\sim q) \ve

Vedclass · Accepted Answer

$p \wedge q$

Vedclass · Answer

(A) Let the given expression be $S = (p \wedge (\sim q)) \vee (\sim p)$.Using the distributive law,we have:$S = (p \vee (\sim p)) \wedge ((\sim q) \vee (\sim p))$Since $(p \vee (\sim p))$ is a tautology $(T)$,we get:$S = T \wedge ((\sim q) \vee (\sim p)) = (\sim q) \vee (\sim p)$Now,we need to find the negation of $S$:$\sim S = \sim ((\sim q) \vee (\sim p))$Using De Morgan's law,$\sim (A \vee B) = (\sim A) \wedge (\sim B)$:$\sim S = (\sim (\sim q)) \wedge (\sim (\sim p))$$\sim S = q \wedge p = p \wedge q$Thus,the negation is equivalent to $p \wedge q$.

The negation of $(p \wedge (\sim q)) \vee (\sim p)$ is equivalent to:

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