The net enthalpy change of a reaction is the | vedclass

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(A) The enthalpy change of a reaction is calculated using the formula: $\Delta_{r}H^{\circ} = \Sigma BE 	ext{ (Reactants)} - \Sigma BE 	ext{ (Produc

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$-109 \ kJ \ mol^{-1}$

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(A) The enthalpy change of a reaction is calculated using the formula: $\Delta_{r}H^{\circ} = \Sigma BE 	ext{ (Reactants)} - \Sigma BE 	ext{ (Products)}$.Given:$BE(H_2) = 435 \ kJ \ mol^{-1}$$BE(Br_2) = 192 \ kJ \ mol^{-1}$$BE(HBr) = 368 \ kJ \ mol^{-1}$For the reaction $H_{2(g)} + Br_{2(g)} 	o 2HBr_{(g)}$:$\Delta_{r}H^{\circ} = [BE(H-H) + BE(Br-Br)] - [2 	imes BE(H-Br)]$$\Delta_{r}H^{\circ} = [435 + 192] - [2 	imes 368] \ kJ \ mol^{-1}$$\Delta_{r}H^{\circ} = 627 - 736 \ kJ \ mol^{-1}$$\Delta_{r}H^{\circ} = -109 \ kJ \ mol^{-1}$

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