(C) The number of days from $January \, 1^{st}$ to $January \, 24^{th}$ is $23 \, days$.The number of half-lives $n$ is calculated as $n = \frac{23}{8

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(C) The number of days from $January \, 1^{st}$ to $January \, 24^{th}$ is $23 \, days$.The number of half-lives $n$ is calculated as $n = \frac{23}{8.04} \approx 2.86$.Since $n After $3$ half-lives,the activity would be $A = A_0 \times (1/2)^3 = 600 \times (1/8) = 75 \, Bq$.Because the elapsed time $(23 \, days)$ is less than $3$ half-lives $(3 \times 8.04 = 24.12 \, days)$,the remaining activity must be greater than $75 \, Bq$.

Class 12 Physics Nuclei Law of Radioactivity by Rutherford and Soddy and Half Life and Mean Life

Medium

The nuclide $^{133}I$ is radioactive,with a half-life of $8.04 \, days$. At noon on $January \, 1$,the activity of a certain sample is $600 \, Bq$. The activity at noon on $January \, 24$ will be

A
$75 \, Bq$
B
Less than $75 \, Bq$
C
More than $75 \, Bq$
D
$150 \, Bq$

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Nuclei

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Law of Radioactivity by Rutherford and Soddy and Half Life and Mean Life

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The nuclide $^{133}I$ is radioactive,with a half-life of $8.04 \, days$. At noon on $January \, 1$,the activity of a certain sample is $600 \, Bq$. The activity at noon on $January \, 24$ will be

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