The number of sp^2 - sp^2 sigma bonds in the | vedclass

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(C) The compound is bicyclo[$4.2$.$0$]octa$-1,3,5-$triene (benzocyclobutene). In the given structure,there are $sp^2$ hybridized carbon atoms involved

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$4$

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(C) The compound is bicyclo[$4.2$.$0$]octa$-1,3,5-$triene (benzocyclobutene). In the given structure,there are $sp^2$ hybridized carbon atoms involved in the double bonds and the ring fusion. Specifically,the $sp^2 - sp^2$ $\sigma$ bonds are found between the carbon atoms that are both $sp^2$ hybridized. Looking at the structure: $1$. There are two $sp^2 - sp^2$ $\sigma$ bonds within the two double bonds of the six-membered ring. $2$. There is one $sp^2 - sp^2$ $\sigma$ bond between the two double bonds in the six-membered ring. $3$. There is one $sp^2 - sp^2$ $\sigma$ bond in the double bond of the four-membered ring. Total $sp^2 - sp^2$ $\sigma$ bonds $= 2 + 1 + 1 = 4$.

The number of $sp^2 - sp^2$ sigma bonds in the compound given below is

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