The number of sp^2 hybridised carbons present | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) Aspartame is a dipeptide methyl ester. Its structure contains: $1$. One carboxylic acid group carbon $(C=O)$: $1$ $sp^2$ carbon. $2$. One amide gr

Vedclass · Accepted Answer

$9$

Vedclass · Answer

(C) Aspartame is a dipeptide methyl ester. Its structure contains: $1$. One carboxylic acid group carbon $(C=O)$: $1$ $sp^2$ carbon. $2$. One amide group carbon $(C=O)$: $1$ $sp^2$ carbon. $3$. One ester group carbon $(C=O)$: $1$ $sp^2$ carbon. $4$. One phenyl ring $(C_6H_5)$: $6$ $sp^2$ carbons. Total number of $sp^2$ hybridised carbons = $1 + 1 + 1 + 6 = 9$.

The number of $sp^2$ hybridised carbons present in "Aspartame" is

Similar Questions

The tripeptide hormone present in most living cells is...

The Biuret test is not given by which of the following?

In an amino acid,the carboxylic group ionises at $pH = 2.56$ $(pK_{a_1})$ and the ammonium ion ionises at $pH = 9.38$ $(pK_{a_2})$. The isoelectric point of the amino acid is at:

The proteins with a prosthetic group are called

Biuret test is used for the detection of

Vedclass Test Series

Exam Paper Generator

Online Exam Module