The number of sigma and pi bonds in peroxodis | vedclass

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Question

(B) The structure of peroxodisulphuric acid $(H_2S_2O_8)$ is $HO-SO_2-O-O-SO_2-OH$. In this structure,there are $4$ $S=O$ bonds (each containing $1$ $

Vedclass · Accepted Answer

$11$ and $4$

Vedclass · Answer

(B) The structure of peroxodisulphuric acid $(H_2S_2O_8)$ is $HO-SO_2-O-O-SO_2-OH$. In this structure,there are $4$ $S=O$ bonds (each containing $1$ $\sigma$ and $1$ $\pi$ bond),$2$ $S-OH$ bonds,$2$ $S-O$ bonds,and $1$ $O-O$ bond. Total $\sigma$ bonds = $4$ (from $S=O$) + $2$ (from $S-OH$) + $2$ (from $S-O$) + $1$ (from $O-O$) + $2$ (from $O-H$) = $11$ $\sigma$ bonds. Total $\pi$ bonds = $4$ (from $S=O$) = $4$ $\pi$ bonds. Hence,it contains $11$ $\sigma$ and $4$ $\pi$ bonds.

The number of $\sigma$ and $\pi$ bonds in peroxodisulphuric acid are,respectively

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Assertion : Bond angle of $H_2S$ is smaller than $H_2O$.
Reason : Electronegativity of the central atom increases,bond angle decreases.

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