The number of asymmetric carbon atoms in the | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The chemical formula for glucose is $CH_2OH-(CHOH)_4-CHO$.In the open-chain structure of glucose,there are $6$ carbon atoms in total.The carbon at

Vedclass · Accepted Answer

$4$

Vedclass · Answer

(C) The chemical formula for glucose is $CH_2OH-(CHOH)_4-CHO$.In the open-chain structure of glucose,there are $6$ carbon atoms in total.The carbon atom at position $1$ is part of the aldehyde group $(-CHO)$,and the carbon atom at position $6$ is part of the primary alcohol group $(-CH_2OH)$.The carbon atoms at positions $2, 3, 4,$ and $5$ are each bonded to four different groups ($-H, -OH, -CHO/CH_2OH,$ and the rest of the carbon chain).Therefore,these $4$ carbon atoms are asymmetric (chiral) centers.Thus,the total number of asymmetric carbon atoms in a glucose molecule is $4$.

The number of asymmetric carbon atoms in the glucose molecule is:

Similar Questions

In aldotriose and ketotriose,which carbon atoms are attached to the aldehyde $(-CHO)$ and ketone $(>C=O)$ groups,respectively?

Which monosaccharide molecules are typically involved in the formation of disaccharides?

Glycogen on hydrolysis gives:

Which of the following is $NOT$ a characteristic of a monosaccharide?

The other name for glucose is ......

Vedclass Test Series

Exam Paper Generator

Online Exam Module