The number of electrons delivered at the cathode during electrolysis by a current of $1 \ A$ in $60 \ s$ is (charge on electron $= 1.60 \times 10^{-19} \ C$)

  • A
    $6 \times 10^{23}$
  • B
    $6 \times 10^{20}$
  • C
    $3.75 \times 10^{20}$
  • D
    $7.48 \times 10^{23}$

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