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(D) The total number of electrons in $O_2^{2-}$ is $8 + 8 + 2 = 18$.The molecular orbital configuration is:$(\sigma 1s)^2, (\sigma^* 1s)^2, (\sigma 2s

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$10, 8$

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(D) The total number of electrons in $O_2^{2-}$ is $8 + 8 + 2 = 18$.The molecular orbital configuration is:$(\sigma 1s)^2, (\sigma^* 1s)^2, (\sigma 2s)^2, (\sigma^* 2s)^2, (\sigma 2p_z)^2, (\pi 2p_x)^2, (\pi 2p_y)^2, (\pi^* 2p_x)^2, (\pi^* 2p_y)^2$Bonding electrons $(N_b)$ = $2 (\sigma 1s) + 2 (\sigma 2s) + 2 (\sigma 2p_z) + 2 (\pi 2p_x) + 2 (\pi 2p_y) = 10$Antibonding electrons $(N_a)$ = $2 (\sigma^* 1s) + 2 (\sigma^* 2s) + 2 (\pi^* 2p_x) + 2 (\pi^* 2p_y) = 8$Therefore,the number of electrons in bonding and antibonding orbitals is $10$ and $8$ respectively.

List-$I$	List-$II$
$(1)$ ${\rm{NO}}$	$(A)$ $1.5$
$(2)$ ${\rm{CO}}$	$(B)$ $2.0$
$(3)$ ${\rm{O}}_2^-$	$(C)$ $2.5$
$(4)$ ${\rm{O}}_2$	$(D)$ $3.0$

The number of electrons present in bonding and antibonding orbitals in $O_2^{2-}$ is respectively

Similar Questions

Thermal decomposition of $AgNO_3$ produces two paramagnetic gases. The total number of electrons present in the antibonding molecular orbitals of the gas that has the higher number of unpaired electrons is. . . . .

Which of the following species have the same bond order: $H_2^+$,$He_2^-$,and $He_2^{2-}$?

Which of the following species,$O_2$,$O_2^+$,and $O_2^-$,has the lowest bond order?

Match the species given in List-$I$ with their bond orders given in List-$II$.

List-$I$ List-$II$

$(1)$ ${\rm{NO}}$ $(A)$ $1.5$

$(2)$ ${\rm{CO}}$ $(B)$ $2.0$

$(3)$ ${\rm{O}}_2^-$ $(C)$ $2.5$

$(4)$ ${\rm{O}}_2$ $(D)$ $3.0$

Which information is obtained from the electronic configuration of a molecule in $MO$ theory?

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