The number of halobenzenes from the following | vedclass

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(D) Sandmeyer's reaction involves the treatment of benzene diazonium salts with $CuCl/HCl$ or $CuBr/HBr$ to yield chlorobenzene or bromobenzene,respec

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$2$

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(D) Sandmeyer's reaction involves the treatment of benzene diazonium salts with $CuCl/HCl$ or $CuBr/HBr$ to yield chlorobenzene or bromobenzene,respectively.Among the given structures:$I$: Fluorobenzene (prepared by Balz-Schiemann reaction)$II$: Chlorobenzene (prepared by Sandmeyer's reaction)$III$: Bromobenzene (prepared by Sandmeyer's reaction)$IV$: Iodobenzene (prepared by treatment with $KI$)$V$: Astatobenzene (not prepared by Sandmeyer's reaction)Thus,only $II$ and $III$ can be prepared by Sandmeyer's reaction.The total number is $2$.

The number of halobenzenes from the following that can be prepared by Sandmeyer's reaction is . . . . . . . . .

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