The number of isomers of [Co(dien)Cl_3] is | vedclass

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(A) The complex $[Co(dien)Cl_3]$ contains a tridentate ligand,diethylenetriamine $(dien)$.This complex exists in two geometrical isomeric forms: $fac$

Vedclass · Accepted Answer

$2$

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(A) The complex $[Co(dien)Cl_3]$ contains a tridentate ligand,diethylenetriamine $(dien)$.This complex exists in two geometrical isomeric forms: $fac$ (facial) and $mer$ (meridional) isomers.In the $fac$-isomer,the three donor nitrogen atoms of the $dien$ ligand and the three $Cl^-$ ions occupy the corners of the same face of the octahedron.In the $mer$-isomer,the three donor nitrogen atoms of the $dien$ ligand and the three $Cl^-$ ions are arranged in a meridional plane.Therefore,the total number of isomers is $2$.

List-$I$ (Complex)	List-$II$ (Type of isomerism)
$A$. $[Co(NH_3)_5(NO_2)]Cl_2$	$I$. Solvate isomerism
$B$. $[Co(NH_3)_5(SO_4)]Br$	$II$. Linkage isomerism
$C$. $[Co(NH_3)_6][Cr(CN)_6]$	$III$. Ionization isomerism
$D$. $[Co(H_2O)_6]Cl_3$	$IV$. Coordination isomerism

The number of isomers of $[Co(dien)Cl_3]$ is

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